Is 'Pi' the answer for 'n' in Fermat?

Cause it seems to work pretty damn well (3.14159) I must be screwing something up, but the calculator gives me the same results each time no matter the numbers I use for x, y and z. 4 Pi Squared, plus 5 Pi Squared equals 9 Pi Squared. LOL Im sure you guys must be laughing your butts off at me, but I was bored one night, and I don't think about typical stuff in my boredom as you can see. 

I mean didn't that French SOB say the proof was ridiculously simple? LOLOL


4Pi^2 + 5Pi^2 = 9Pi^2 is not a solution to Fermat - you're only dealing with powers of 2!

Fermat's theorem is x^n + y^n = z^n  - where n is greater 2

Can you give us an example which makes this true where n = Pi?


Using Windows' own calculator:

4^Pi = 77.880233648388115107020834778598

5^Pi = 156.99254530886590757845919883265

9^Pi = 995.04164489285525428416364538181


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